Question 10a

ABCD is a parallelogram. DG is a straight line. ∠ABC = 65°, ∠CAD = 50° and ∠CFG = 140°. Find ∠BAC. (1 mark)

$Question 10a diagram$

Answer: 65 °

Workings

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∠ BAC = ∠ BAD (green) - 50

∠ BAD (green) → 180 - 65 = 115

∠ BAC = ∠ BAD (green) - 50 = 115 - 50 = 65

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