Jane had enough money to buy either 8 identical bags or 12 identical dresses. Each bag cost $15.30 more than each dress. How much money did Jane have? (3 marks)
Answer: $ 367.20
let b be bag let d be dress
"Jane had enough money to buy either 8 identical bags or 12 identical dresses."
8b = 12d
Each bag cost $15.30 more than each dress.
b → $15.30 + 1d
8b → $15.30 x 8 + 1d x 8 = $122.40 + 8d
since 8 bags is the same cost as 12 dresses
12d = $122.40 + 8d 12d - 8d = $122.40 + 8d - 8d 4d = $122.40 1d = 122.40 ÷ 4 = $30.60
12d (total money) → 12 x 30.60 = $367.20
let b be bag let d be dress
"Jane had enough money to buy either 8 identical bags or 12 identical dresses."
8b = 12d
Each bag cost $15.30 more than each dress.
b → $15.30 + 1d
8b → $15.30 x 8 + 1d x 8 = $122.40 + 8d
since 8 bags is the same cost as 12 dresses
12d = $122.40 + 8d 12d - 8d = $122.40 + 8d - 8d 4d = $122.40 1d = 122.40 ÷ 4 = $30.60
12d (total money) → 12 x 30.60 = $367.20